Szewce, Kuyavian-Pomeranian Voivodeship

Village in Kuyavian-Pomeranian Voivodeship, Poland
52°31′N 18°29′E / 52.517°N 18.483°E / 52.517; 18.483Country PolandVoivodeshipKuyavian-PomeranianCountyRadziejówGminaPiotrków Kujawski

Szewce [ˈʂɛft͡sɛ] is a village in the administrative district of Gmina Piotrków Kujawski, within Radziejów County, Kuyavian-Pomeranian Voivodeship, in north-central Poland.[1] It lies approximately 4 kilometres (2 mi) south of Piotrków Kujawski, 14 km (9 mi) south of Radziejów, and 59 km (37 mi) south of Toruń.

References

  1. ^ "Central Statistical Office (GUS) – TERYT (National Register of Territorial Land Apportionment Journal)" (in Polish). 2008-06-01.


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