Tsankov Island

Antarctic island

65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W / -65.06611; -64.14389ArchipelagoWilhelm ArchipelagoArea9.48 ha (23.4 acres)Length625 m (2051 ft)Width216 m (709 ft)AdministrationAdministered under the Antarctic Treaty SystemDemographicsPopulationuninhabited

Tsankov Island (Bulgarian: Цанков остров, romanized: Tsankov ostrov, IPA: [t͡sɐnˈkɔf ˈɔstrof]) is the mostly ice-covered island 625 m long in west-southwest to west-northeast direction and 216 m wide in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 9.48 ha.[1]

The feature is named after the dermatologist Nikolay Tsankov, participant in the 2010/11 and subsequent Bulgarian Antarctic campaigns.[1]

Location

Tsankov Island is located at 65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W / -65.06611; -64.14389, which is 293 m northwest of Stego Island, 175 m east of Bodloperka Island, 1.18 km southeast of Sprey Island and 1.25 km west-southwest of Taralezh Island. British mapping in 2001.

Maps

  • British Admiralty Nautical Chart 446 Anvers Island to Renaud Island. Scale 1:150000. Admiralty, UK Hydrographic Office, 2001
  • Brabant Island to Argentine Islands. Scale 1:250000 topographic map. British Antarctic Survey, 2008
  • Antarctic Digital Database (ADD). Scale 1:250000 topographic map of Antarctica. Scientific Committee on Antarctic Research (SCAR). Since 1993, regularly upgraded and updated

See also

Notes

  1. ^ a b Tsankov Island. SCAR Composite Gazetteer of Antarctica

References

  • Tsankov Island. Adjusted Copernix satellite image

This article includes information from the Antarctic Place-names Commission of Bulgaria which is used with permission.


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