Synkowce
Village in Podlaskie Voivodeship, Poland
53°37′N 23°30′E / 53.617°N 23.500°E / 53.617; 23.500![](http://upload.wikimedia.org/wikipedia/en/thumb/1/12/Flag_of_Poland.svg/23px-Flag_of_Poland.svg.png)
Synkowce [sɨŋˈkɔft͡sɛ] is a village in the administrative district of Gmina Nowy Dwór, within Sokółka County, Podlaskie Voivodeship, in north-eastern Poland, close to the border with Belarus.[1] It lies approximately 25 kilometres (16 mi) north of Sokółka and 60 km (37 mi) north of the regional capital Białystok.
References
- ^ "Central Statistical Office (GUS) – TERYT (National Register of Territorial Land Apportionment Journal)" (in Polish). 2008-06-01.
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