Roseville, Iowa

Census-designated place in Iowa, United States

43°0′36″N 92°48′43″W / 43.01000°N 92.81194°W / 43.01000; -92.81194CountryUnited StatesStateIowaCountyFloydTownshipUlster and UnionArea

^[1]

• Total3.69 sq mi (9.56 km²) • Land3.69 sq mi (9.56 km²) • Water0.00 sq mi (0.00 km²)Population

(2020)

• Total39 • Density10.56/sq mi (4.08/km²)Time zoneCentral (CST)FIPS code19-68800

Roseville is a census-designated place^[2] mainly located in Ulster Township and a small portion in the northern part of Union Township in Floyd County in the state of Iowa. As of the 2010 census the population was 49.^[3]

Its location is approximately 6 miles (10 km) northeast of the city of Marble Rock or 11 miles (18 km) southwest of the city of Charles City, along Iowa Highway 14.

Demographics

Historical population
Census	Pop.	Note	%±
2020	39		—
U.S. Decennial Census^[4]

References

^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
^ [1]^{[dead link]}
^ "Decennial Census of Population and Housing by Decades".
^ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.