Singles |
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1988 Seoul Open |
Final |
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Champion | Dan Goldie |
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Runner-up | Andrew Castle |
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Score | 6–3, 6–7(5–7), 6–0 |
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Details |
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Draw | 32 |
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Seeds | 8 |
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Events |
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1988 tennis event results
Jim Grabb was the defending champion, but lost in the first round this year.
Dan Goldie won the tournament, beating Andrew Castle in the final, 6–3, 6–7(5–7), 6–0.[1][2]
Seeds
Andre Agassi (second round)
Eliot Teltscher (semifinals)
John Fitzgerald (quarterfinals)
John Frawley (quarterfinals)
Dan Goldie (champions)
Jim Grabb (first round)
Joey Rive (quarterfinals)
Todd Nelson (quarterfinals)
Draw
Key
Finals
Top half
Bottom half
References
- ^ "Goldie Wins 3-Setter for Title in South Korea". Los Angeles Times. Seoul, South Korea. Associated Press. 25 April 1988. Retrieved 10 November 2023.
- ^ John Barrett, ed. (1988). The International Tennis Federation : World of Tennis 1988. London: Willow Books. p. 153. ISBN 9780002182690.
External links